Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set: 28

Answer

$(5\sqrt3, -4)$

Work Step by Step

RECALL: The midpoint of $(x_1, y_1)$ and $(x_2, y_2)$ can be found using the midpoint formula $\text{midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$ Use the formula above to obtain: $\text{midpoint} \\=\left(\dfrac{7\sqrt3+3\sqrt3}{2}, \dfrac{-6+(-2)}{2}\right) \\=\left(\dfrac{10\sqrt3}{2}, \dfrac{-8}{2}\right) \\=(5\sqrt3, -4)$
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