Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 765: 40

Answer

$\\(x+2)^2+y^2=36$

Work Step by Step

RECALL: The standard form of the equation of a circle with a center of $(h, k)$ and a radius of $r$ units is: $(x-h)^2 + (y-k)^2 = r^2$ The given circle has its center at $(-2, 0)$ and a radius of $6$ units. Use the standard form above where $h=-2$, $k=0$ and $r=6$ to obtain: $[x-(-2)]^2 + (y-0)^2 =6^2 \\(x+2)^2+y^2=36$
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