Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - Chapter Review Exercises - Page 542: 41

Answer

$x \approx 0.466$

Work Step by Step

$3(5^{3x+2})-700=11$ $3(5^{3x+2})=11+700$ $3(5^{3x+2})=711$ $(5^{3x+2})=\frac{711}{3}$ $(5^{3x+2})=237$ $\log5^{3x+2}= \log237$ $(3x+2)\log5=\log237$ $3x+2=\frac{\log237}{\log5}$ $3x+2=3.397$ $3x=3.397-2$ $3x=1.397$ $x=\frac{1.397}{3}$ $x \approx 0.466$
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