Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - Chapter Review Exercises - Page 542: 39

Answer

$x\approx1.841$

Work Step by Step

Isolate the exponential term on one side. Then take the log of both sides, and then use the power property. $17(1.9)^x=55.4$ $1.9^x=\frac{55.4}{17}$ $x\log1.9=\log\frac{55.4}{17}$ $x=\frac{\log\frac{55.4}{17}}{\log1.9}$ $x\approx1.841$
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