Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.5 Solving Equations by Factoring - 4.5 Exercises - Page 362: 95

Answer

$x=2$

Work Step by Step

Simplify the equation to obtain: \begin{align*} 4m^2+5m-4m^2&=0\\ 5m&=10 \end{align*} Divide $5$ to both sides to obtain: $$m=2$$ Checking: \begin{align*} 4(2^2)+5(2)&=4(2^2)+10\\ 4(4)+10&\stackrel{\checkmark}=4(4)+10\\ \end{align*} Therefiore, the solution set is $x=2$.
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