Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.5 Solving Equations by Factoring - 4.5 Exercises - Page 362: 88

Answer

The solution set is $\left\{-4, 4\right\}$.

Work Step by Step

Divide $5$ to both sides: \begin{align*} w^2&=16\end{align*} Take the square root of both sides to obtain: \begin{align*} \sqrt{w^2}&=\pm\sqrt{16}\\ w&=\pm4\\ \end{align*} Checking: \begin{align*} 5(-4)^2&=80\\ 5(16)&=80\\ 80&\stackrel{\checkmark}=80 \end{align*} \begin{align*} 5(4^2)&=80\\ 5(16)&=80\\ 80&\stackrel{\checkmark}=80 \end{align*} Thus, the solution set is $\left\{-4, 4\right\}$.
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