Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Test - Page 533: 11

Answer

$x=3\pm\sqrt{7}$

Work Step by Step

Using the completing the square method, the solutions to the given equation, $ x^2-6x=-2 $, are \begin{array}{l}\require{cancel} x^2-6x+\left( \dfrac{-6}{2} \right)^2=-2+\left( \dfrac{-6}{2} \right)^2 \\\\ x^2-6x+9=-2+9 \\\\ (x-3)^2=7 \\\\ x-3=\pm\sqrt{7} \\\\ x=3\pm\sqrt{7} .\end{array}
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