## Intermediate Algebra (6th Edition)

x=$\frac{3±\sqrt 8}{2}$
Original Equation (2x-3)²=8 Take the square root of both sides 2x-3=±$\sqrt 8$ Add 3 to both sides 2x=3±$\sqrt 8$ Divide both sides by 2 x=$\frac{3±\sqrt 8}{2}$