Chapter 8 - Section 8.1 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 482: 9

The solutions are $x=-2$ and $x=-8$

$(x+5)^{2}=9$ Take the square root of both sides of the equation: $\sqrt{(x+5)^{2}}=\pm\sqrt{9}$ $x+5=\pm3$ Solve for $x$: $x=\pm3-5$ $x=3-5=-2$ $x=-3-5=-8$ The solutions are $x=-2$ and $x=-8$