Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 446: 92b

Answer

$\dfrac{\sqrt[3]{10y}}{2}$

Work Step by Step

Multiplying the numerator and the denominator of the given expression, $ \dfrac{\sqrt[3]{5y}}{\sqrt[3]{4}} ,$ by $ \sqrt[3]{2} $ results to \begin{array}{l}\require{cancel} \dfrac{\sqrt[3]{5y}}{\sqrt[3]{4}}\cdot\dfrac{\sqrt[3]{2}}{\sqrt[3]{2}} \\\\= \dfrac{\sqrt[3]{5y(2)}}{\sqrt[3]{4(2)}} \\\\= \dfrac{\sqrt[3]{10y}}{\sqrt[3]{8}} \\\\= \dfrac{\sqrt[3]{10y}}{\sqrt[3]{(2)^3}} \\\\= \dfrac{\sqrt[3]{10y}}{2} .\end{array}
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