Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 446: 87

Answer

$x=\left\{ 2, 6 \right\}$

Work Step by Step

Factoring the equation and then equating each factor to zero (Zero-Product Property), then the values of $x$ that satisfy the given equation, $ x^2-8x=-12 ,$ are \begin{array}{l}\require{cancel} x^2-8x+12=0 \\\\ (x-6)(x-2)=0 \\\\ x-6=0 \\\\ x=6 ,\\\\\text{OR}\\\\ x-2=0 \\\\ x=2 .\end{array} Hence, $ x=\left\{ 2, 6 \right\} .$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.