Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Sections 11.1-11.3 - Integrated Review - Sequences and Series - Page 653: 6

Answer

$a_4=-14$

Work Step by Step

Substituting $n=4$ in $-n^2+2$, then, \begin{array}{l} a_4=-4^2+2\\ a_4=-16+2\\ a_4=-14 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.