Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Sections 11.1-11.3 - Integrated Review - Sequences and Series - Page 653: 10

Answer

$\left\{ -3,-15,-75,-375,-1,875 \right\} $

Work Step by Step

With $a_1=-3$ and $r=5$, then \begin{array}{l} a_{1}=-3 ,\\\\ a_2=a_1r\\ a_2=(-3)(5)\\ a_2=-15 ,\\\\ a_3=a_2r\\ a_3=(-15)(5)\\ a_3=-75 ,\\\\ a_4=a_3r\\ a_4=-75(5)\\ a_4=-375 ,\\\\ a_5=a_4r\\ a_5=-375(5)\\ a_5=-1,875 .\end{array} Hence, the first 5 terms are $ \left\{ -3,-15,-75,-375,-1,875 \right\} $
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