Answer
TRUE
Work Step by Step
The results of (a) and (b) show that the constant expression in the summation symbol can be factored out of the summation symbol. Hence, $
\displaystyle\sum_{i=1}^n c\cdot a_n=c\cdot\displaystyle\sum_{i=1}^n a_n
$.
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Section 11.3 - Series - Exercise Set - Page 652: 60d
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