Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set: 53

Answer

$\frac{10}{27}$

Work Step by Step

Plug in and use PEMDAS (parentheses, exponentiation, multiplication, division, addition, subtraction) to determine which operation goes first. $\frac{\frac{1}{3}}{1-\frac{1}{10}} = \frac{\frac{1}{3}\cdot3}{\frac{9}{10}\cdot3} = \frac{1}{\frac{27}{10}} = \frac{1\cdot10}{\frac{27}{10}\cdot10} = \frac{10}{27}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.