Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 29b

Answer

$\dfrac{5\sqrt[3]{7x}}{2}$

Work Step by Step

Using the properties of radicals, the expression $ \sqrt[3]{\dfrac{7x}{8}}+2\sqrt[3]{7x} $ simplifies to \begin{array}{l} \dfrac{\sqrt[3]{7x}}{2}+2\sqrt[3]{7x} \\\\= \dfrac{1(\sqrt[3]{7x})+2(2\sqrt[3]{7x})}{2} \\\\= \dfrac{\sqrt[3]{7x}+4\sqrt[3]{7x}}{2} \\\\= \dfrac{5\sqrt[3]{7x}}{2} .\end{array}
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