Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 22a

Answer

$2\sqrt{2}$

Work Step by Step

Using the properties of radicals, the expression $ \dfrac{\sqrt{32}}{\sqrt{4}} $ simplifies to \begin{array}{l} \sqrt{\dfrac{32}{4}} \\\\= \sqrt{8} \\\\= \sqrt{4\cdot2} \\\\= 2\sqrt{2} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.