Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.7 - Complex Numbers - 7.7 Exercises - Page 491: 44

Answer

$1-4i$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To simplify the given expression, $ [(7+2i)+(-4-i)]-(2+5i) ,$ remove the grouping symbols first. Then combine the real numbers and combine the imaginary numbers $\bf{\text{Solution Details:}}$ Removing the grouping symbols, the expression above is equivalent to \begin{array}{l}\require{cancel} [7+2i-4-i]-(2+5i) \\\\= 7+2i-4-i-2-5i .\end{array} Combining the real numbers and combining the imaginary numbers result to \begin{array}{l}\require{cancel} (7-4-2)+(2i-i-5i) \\\\= 1-4i .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.