Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.7 - Complex Numbers - 7.7 Exercises: 20

Answer

$4i\sqrt 6$

Work Step by Step

$\sqrt -96=\sqrt (-1\times16\times6)=\sqrt -1\times\sqrt 16\times\sqrt6=(i\times4\times\sqrt6)=4i\sqrt 6$ We know that $\sqrt -1=i$, because $i^{2}=-1$.
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