Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Review Exercises: 33

Answer

$7^{\frac{9}{2}}$

Work Step by Step

We are given that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=(\sqrt[n] a)^{m}$, if all indicated roots are real numbers. Therefore, $\sqrt 7^{9}=\sqrt[2] 7^{9}=7^{\frac{9}{2}}$.
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