Answer
32
Work Step by Step
We are given that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=(\sqrt[n] a)^{m}$, if all indicated roots are real numbers.
Therefore, $16^{\frac{5}{4}}=\sqrt[4] 16^{5}=(\sqrt[4] 16)^{5}=(2)^{5}=32$.
We know that $\sqrt[4] 16=2$, because $2^{4}=16$.
