Answer
$\frac{a(a+1)}{a+3}$
Work Step by Step
We can remove a factor of : $\frac{a+1}{a+1}=1$
$\frac{a^3+2a^2+a}{a^2+4a+3}=\frac{a(a^2+2a+1)}{(a+1)(a+3)}=\frac{a(a+1)(a+1)}{(a+1)(a+3)}=\frac{a(a+1)}{a+3}$
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