Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.6 Rational Expressions and Equations - R.6 Exercise Set - Page 980: 6

Answer

$\frac{1}{3}$

Work Step by Step

We can remove a factor of : $\frac{2(x+5)}{2(x+5)}=1$ $\frac{2x+10}{6x+30}=\frac{2(x+5)}{6(x+5)}=\frac{1}{3}$
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