Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.4 Polynomials - R.4 Exercise Set: 9

Answer

$\dfrac{1}{a^2b^{2}}$

Work Step by Step

Using $a^{-n}=\dfrac{1}{a^n}$, the given expression, $ (ab)^{-2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{1}{(ab)^{2}} \\\\= \dfrac{1}{a^2b^{2}} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.