Answer
$x^{8}y^{12}$
Work Step by Step
Using the laws of exponents, the given expression, $
\left( x^{-2}y^{-3} \right)^{-4}
,$ simplifies to
\begin{array}{l}\require{cancel}
x^{-2(-4)}y^{-3(-4)}
\\\\=
x^{8}y^{12}
.\end{array}
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