Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.1 Introduction to Algebraic Expressions - R.1 Exercise Set: 52

Answer

$-\dfrac{7}{100}$

Work Step by Step

The given expression, $ \dfrac{3-2\times6-5}{2(3+7)^2} ,$ evaluates to \begin{array}{l}\require{cancel} \dfrac{3-12-5}{2(10)^2} \\\\= \dfrac{-9-5}{2(100)} \\\\= \dfrac{-14}{200} \\\\= \dfrac{\cancel{2}\cdot(-7)}{\cancel{2}\cdot100} \\\\= \dfrac{-7}{100} \\\\= -\dfrac{7}{100} .\end{array}
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