Answer
$-\dfrac{7}{100}$
Work Step by Step
The given expression, $
\dfrac{3-2\times6-5}{2(3+7)^2}
,$ evaluates to
\begin{array}{l}\require{cancel}
\dfrac{3-12-5}{2(10)^2}
\\\\=
\dfrac{-9-5}{2(100)}
\\\\=
\dfrac{-14}{200}
\\\\=
\dfrac{\cancel{2}\cdot(-7)}{\cancel{2}\cdot100}
\\\\=
\dfrac{-7}{100}
\\\\=
-\dfrac{7}{100}
.\end{array}
