Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.1 Introduction to Algebraic Expressions - R.1 Exercise Set - Page 938: 14

Answer

$\dfrac{5}{8}$

Work Step by Step

Using operations on real numbers, the given expression, $ \dfrac{3}{8}\div\dfrac{3}{5} ,$ evaluates to \begin{array}{l}\require{cancel} \dfrac{3}{8}\cdot\dfrac{5}{3} \\\\= \dfrac{\cancel{3}}{8}\cdot\dfrac{5}{\cancel{3}} \\\\= \dfrac{5}{8} .\end{array}
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