Answer
$6a^2-19a+10$
Work Step by Step
Distribute each term of the first factor to the second factor to obtain:
$=3a(2a-5) -2(2a-5)$
Distribute $3a$ and $2$ to obtain:
$=3a(2a)-3a(5) -2(2a)-2(-5)
\\=6a^2-15a-4a-(-10)
\\=6a^2-19a+10$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 5 - Polynomials and Factoring - Connecting: The Concepts - Exercises - Page 350: 8
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