Answer
$(n-9)(n-1)$
Work Step by Step
RECALL:
A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$.
The trinomial's factored form will be:
$x^2+bx+c=(x+d)(x+e)$
The given trinomial has $b=-10$ and $c=9$.
Note that $9=-9(-1)$ and $-10= -9+(-1)$.
This means that $d=-9$ and $e=-1$
Thus, the factored form of the trinomial is: $[n+(-9)][n+(-1)] = (n-9)(n-1)$.
