Answer
$(x+12)(x-5)$
Work Step by Step
In decreasing order of exponents, the given expression, $
7x-60+x^2
,$ is equivalent to
\begin{array}{l}
x^2+7x-60
.\end{array}
The 2 numbers whose product is $ac=
1(-60)=-60
$ and whose sum is $b=
7
$ are $\left\{
12,-5
\right\}.$ Using these two numbers to decompose the middle term of the above trinomial, then
\begin{array}{l}
x^2+12x-5x-60
\\\\=
(x^2+12x)-(5x+60)
\\\\=
x(x+12)-5(x+12)
\\\\=
(x+12)(x-5)
.\end{array}