Answer
$(y+1)(y+7)$
Work Step by Step
The 2 numbers whose product is $ac=
1(7)=7
$ and whose sum is $b=
8
$ are $\left\{
1,7
\right\}.$ Using these two numbers to decompose the middle term of the given trinomial, $
y^2+8y+7
,$ then
\begin{array}{l}\require{cancel}
y^2+1y+7y+7
\\\\=
(y^2+y)+(7y+7)
\\\\=
y(y+1)+7(y+1)
\\\\=
(y+1)(y+7)
.\end{array}