Answer
all real numbers
Work Step by Step
$\bf{\text{Solution Outline:}}$
The domain of the given function, $
f(t)=\sqrt[5]{2t+7}
,$ is the permissible values of $x.$
$\bf{\text{Solution Details:}}$
With an odd index (index equals $
5
$), then the radicand can be any real number. Hence, the domain is the set of $\text{
all real numbers
.}$