Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.1 Radical Expressions and Functions - 10.1 Exercise Set: 107

Answer

$f\left( \dfrac{1}{3} \right)=0$

Work Step by Step

Substituting $x=\dfrac{1}{3}$ in $f(x)=3x-1,$ then \begin{array}{l}\require{cancel} f(x)=3x-1 \\\\ f\left( \dfrac{1}{3} \right)=3\left( \dfrac{1}{3} \right)-1 \\\\ f\left( \dfrac{1}{3} \right)=1-1 \\\\ f\left( \dfrac{1}{3} \right)=0 .\end{array}
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