Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-9 - Cumulative Review - Page 625: 5

Answer

$$\frac{2}{x^2+5x+25}$$

Work Step by Step

Simplifying by canceling out common factors in the numerator and the denominator, we obtain: $$ \frac{2\left(x-5\right)}{x^3-125}\\ \frac{2\left(x-5\right)}{\left(x-5\right)\left(x^2+5x+25\right)}\\ \frac{2}{x^2+5x+25}$$
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