Answer
$$\frac{2}{x^2+5x+25}$$
Work Step by Step
Simplifying by canceling out common factors in the numerator and the denominator, we obtain:
$$ \frac{2\left(x-5\right)}{x^3-125}\\ \frac{2\left(x-5\right)}{\left(x-5\right)\left(x^2+5x+25\right)}\\ \frac{2}{x^2+5x+25}$$