Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-9 - Cumulative Review - Page 625: 26

Answer

$$t=\frac{c}{a-d};\quad \:a\ne \:d$$

Work Step by Step

Solving by using the rules of Algebra to isolate the variable $t$, we find: $$ t\left(a-d\right)=c\\ t=\frac{c}{a-d};\quad \:a\ne \:d$$
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