Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 8 - Linear Differential Equations of Order n - 8.2 Constant Coefficient Homogeneous Linear Differential Equations - Problems: 8

Answer

$y=C_1e^{2t}+C_2e^{-t}$

Work Step by Step

Solve the characteristic equation for the differential equation. $$r^2-r-2=0$$ Factor and solve for the roots. $$(r-2)(r+1)=0$$ $$r=2,-1$$ The general equation is equal to $y=C_1e^{r_1t}+C_2e^{r_2t}$. Therefore, the solution equals $y=C_1e^{2t}+C_2e^{-t}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.