College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Section 9.1 - Counting - 9.1 Exercises: 10

Answer

$941,094$

Work Step by Step

RECALL: $P(n, r) = \dfrac{n!}{(n-r)!}$ Use the formula above to obtain: $P(99, 3) = \dfrac{99!}{(99-3)!} \\P(99, 3) = \dfrac{99!}{96!} \\P(99, 3) = \dfrac{99(98)(97)(96!)}{96!}$ Cancel the common factor $96!$ to obtain: $P(99, 3) = 99(98)(97) \\P(99, 3) = 941,094$
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