College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Section 9.1 - Counting - 9.1 Exercises: 6

Answer

$ 72$

Work Step by Step

RECALL: $P(n, r) = \dfrac{n!}{(n-r)!}$ Use the formula above to obtain: $P(9, 2) = \dfrac{9!}{(9-2)!} \\P(9, 2) = \dfrac{9!}{7!} \\P(9, 2) = \dfrac{9(8)(7!)}{7!}$ Cancel the common factor $7!$ to obtain: $P(9, 2) = 9(8) \\P(9, 2) = 72$
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