Chapter 5, Systems of Equations and Inequalities - Section 5.1 - Systems of Linear Equations in Two Variations - 5.1 Exercises - Page 446: 33

x=10; y=-9

Multiplying the first equation by 2 and the second equation by 1 gives: $x+\frac{2}{3}y=4$ $\frac{1}{5}x-\frac{2}{3}y=8$ Adding two equations: $\frac{6}{5}x=12 \Rightarrow x=10$ Solve for y: $\frac{1}{5}10-\frac{2}{3}y=-9$