College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 5, Systems of Equations and Inequalities - Section 5.1 - Systems of Linear Equations in Two Variations - 5.1 Exercises - Page 446: 30

Answer

(12, 4)

Work Step by Step

Multiply the first equation by 3 -12x + 36y = 0 Add to the second equation -12x + 36y = 0 12x + 4y = 160 40y = 160 y = 4 Plug y = 4 into 12x + 4y = 160 12x + 4(4) = 160 12x = 144 x = 12 Solution is (12, 4)
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