College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises: 54

Answer

$f^{-1}(x) = \frac{2x + 2}{1 - x}$

Work Step by Step

$f(x) = \frac{x - 2}{x + 2}$ $y = \frac{x - 2}{x + 2}$ y(x + 2) = x - 2 yx + 2y = x - 2 2y + 2 = x - yx 2y + 2 = x( 1 - y) $x = \frac{2y + 2}{1 - y}$ $f^{-1}(x) = \frac{2x + 2}{1 - x}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.