## College Algebra 7th Edition

$f^{-1}(x) = \frac{x - 3}{2 + 5x}$
$f(x) = \frac{2x +3}{1 - 5x}$ $y = \frac{2x +3}{1 - 5x}$ y(1- 5x) = 2x + 3 y - 5xy = 2x + 3 y - 3 = 2x + 5xy y - 3 = x(2 + 5y) $x = \frac{y - 3}{2 + 5y}$ $f^{-1}(x) = \frac{x - 3}{2 + 5x}$