Answer
$f(5)=1$
$f(9)=4-\sqrt 21$
$f(5a+2)=4-\sqrt 3a$
$f(-x)=4-(\sqrt -3x-6)$
$f(x^{2})=4-(\sqrt 3x^{2}-6)$
Work Step by Step
$f(x)=4-\sqrt 3x-6$
Plug in x values into g(x)
$f(5)=4-(\sqrt 3(5)-6)=1$
$f(9)=4-(\sqrt 3(9)-6)=4-\sqrt 21$
$f(a+2)=4-(\sqrt 3(a+2)-6)=4-\sqrt 3a$
$f(-x)=4-(\sqrt 3(-x)-6)=4-(\sqrt -3x-6)$
$f(x^{2})=4-\sqrt 3(x^{2})-6=4-(\sqrt 3x^{2}-6)$
