College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Chapter 2 Review - Exercises - Page 267: 6

Answer

$h(-2)=3$ $h(-1)=-4$ $h(0)=-5$ $h(1)=0$ $h(2)=11$

Work Step by Step

$h(x)=3x^{2}+2x-5$ Plug in x values into g(x) $h(-2)=3(-2)^{2}+2(-2)-5=3$ $h(-1)=3(-1)^{2}+2(-1)-5=-4$ $h(0)=3(0)^{2}+2(0)-5=-5$ $h(1)=3(1)^{2}+2(1)-5=0$ $h(2)=3(2)^{2}+2(2)-5=11$
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