Answer
$3+i$
Work Step by Step
$\displaystyle \frac{(1+2i)(3-i)}{2+i}=\frac{3-i+6i-2i^{2}}{2+i}=\frac{5+5i}{2+i}*\frac{2-i}{2-i}=\frac{10-5i+10i-5i^{2}}{4-i^{2}}=\frac{10+5i-5*-1}{4--1}=\frac{10+5+5i}{5}=\frac{15+5i}{5} =\frac{15}{5}+\frac{5}{5}i=3+i$
