College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.5 - Complex Numbers - 1.5 Exercises: 40

Answer

$\frac{11}{25}-\frac{23}{25}i$

Work Step by Step

$\displaystyle \frac{5-i}{3+4i}=\frac{5-i}{3+4i}*\frac{3-4i}{3-4i}=\frac{15-20i-3i+4i^{2}}{9-16i^{2}}=\frac{15-23i+4*-1}{9-16*-1}=\frac{15-4-23i}{9+16}=\frac{11-23i}{25}=\frac{11}{25}-\frac{23}{25}i$
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