College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Cumulative Review Exercises (Chapters 1-8) - Page 793: 42

Answer

$11$ amps

Work Step by Step

Our equation is: $I=\frac{k}{R}$ and we know that $5=\frac{k}{22}$, so $k=110$. So when $R=10$, then $I=\frac{110}{10}=11$
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