Answer
100
Work Step by Step
Let $x$ be the width, then the length is $50+x$. Then our equation is: $2\cdot(x+(50+x))=300\\2(2x+50)=300\\4x+100=300\\4x=200\\x=50$
Thus the field is $50$ yards wide and $50+50=100$ yards long.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Summary, Review, and Test - Cumulative Review Exercises (Chapters 1-8) - Page 793: 39
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