College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.1 - Systems of Linear Equations - 5.1 Exercises - Page 492: 104

Answer

$a)~q=8$ $b)~q=4$ $c)~q=0$

Work Step by Step

$a)$$$p=16-\frac54 q$$ Substitute $p=6$: $$6=16-\frac54 q$$ $$\frac54q=16-6=10$$ $$q=10\cdot \frac45=8$$ $b)$$$p=16-\frac54 q$$ Substitute $p=11$: $$11=16-\frac54 q$$ $$\frac54q=16-11=5$$ $$q=5\cdot \frac45=4$$ $c)$$$p=16-\frac54 q$$ Substitute $p=16$: $$16=16-\frac54 q$$ $$\frac54q=16-16=0$$ $$q=0\cdot \frac45=0$$
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