College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.1 - Systems of Linear Equations - 5.1 Exercises - Page 492: 103

Answer

$a)~p=16$ $b)~p=11$ $c)~p=6$

Work Step by Step

$a)$$$p=16-\frac54 q$$ Substitute $q=0$: $$p=16-\frac54 (0)=16$$ $b)$$$p=16-\frac54 q$$ Substitute $q=4$: $$p=16-\frac54 (4)=16-5=11$$ $c)$$$p=16-\frac54 q$$ Substitute $q=8$: $$p=16-\frac54 (8)=16-10=6$$
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